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Please help me! (Read 450 times)
Dec 6th, 2003 at 9:42pm

Jared   Offline
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Hey all! I need help again! I’ve gone through 32 of 33 problems on my Take home calculus test which was comprehensive.  Unfortunately I have not been able to figure out how to solve the last one.  I would appreciate any information that anyone might be able to provide.

Thanks,

Jared

Evaluate the following integral at the given points:

⌠ (X + 1) / (X2 + 2X) dx
evaluated at X = 0 for the lower bound, and X = 1 for the upper bound

(The little box in the beginning of the equation is the integral sign..)
 
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Reply #1 - Dec 7th, 2003 at 6:08am

Polynomial   Offline
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is that x to the power of 2?
 
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Reply #2 - Dec 7th, 2003 at 6:39am

Ivan   Offline
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yes i think

Write down the formula on paper (probably you've done that already
Make that into the formula for the line describing the angle (formula, not degrees) of the line that follows the formula in every point.

Put 0.00001 in for the lower
and 0.99999 for the upper limit
 

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Reply #3 - Dec 7th, 2003 at 8:41am

Polynomial   Offline
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Ans = (x+1)*ln(x^2+2*x) + C

because differentiating this;

let y = a * ln u where u = x^2+2*x and a = x + 1

dy/dx = a / u

dy/dx = (x+1) / (x^2+2*x)
 
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Reply #4 - Dec 7th, 2003 at 11:00am

Jared   Offline
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You guys have got the same answer that I have already been  able to find using substitution, however if you take the dy/dx and do:

F(1) - F(0) like we're supposed to do to get the area under the curve, you end up takign the natural log of 0 which is undefined...

One of the other guys from the class went to the tutoring center and got all of the answers, and for this problem they ended up with a 2.25, but he doesn't have any work to show how he got it... Sad
 
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Reply #5 - Dec 7th, 2003 at 11:03am

Lethal.Ambition   Offline
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Well thats not good

"Show your work" is proly my teachers fav saying.

You know, all that I think I prefer taking pre-calculus than Algebra 2!!! Shocked
 

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Reply #6 - Dec 7th, 2003 at 11:13am

Jared   Offline
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I don't know...Calculus can involve lots of algebra also..

Sad I'm not good at algebra, but once I solve this problem, I'll be done with all of the math classes that I have to take! Translation? No more math EVER! Yay!
 
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Reply #7 - Dec 7th, 2003 at 11:22am

Lethal.Ambition   Offline
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Wait, is that like your final?
 

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Reply #8 - Dec 7th, 2003 at 11:42am

flyboy 28   Offline
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Shocked





I think I'll stick with Algebra 2, thank you...Smiley
 
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Reply #9 - Dec 7th, 2003 at 11:43am

Jared   Offline
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Yup! final question to be solved! I was able to get the rest of them myself, but this last one here is just bugging me more than anything else...

I'm sure that I could leave it blank or write it as undefined, but i wanted to be sure to check all my bases and make sure that I did an adequate amount of work before I called it quits... Sad
 
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Reply #10 - Dec 7th, 2003 at 7:13pm

Polynomial   Offline
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im using an almighty graphics calculator with integral function and it gives me an error! How baffling!?! ???
 
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Reply #11 - Dec 7th, 2003 at 8:02pm

Jared   Offline
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Yeah, I got the same problem usign my calculator, also got the information from the guy who went to see the tutor, and from a retired physicist also...

Unfortunately they both got different answers... Sad

Now I'm still trying to figure it out! And it's driving me crazy!  Cheesy Wink
 
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Reply #12 - Dec 7th, 2003 at 8:46pm

Lethal.Ambition   Offline
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I say go with the retired guy. then again, i am just 14 yrs old! ???
 

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Reply #13 - Dec 7th, 2003 at 8:50pm

Jared   Offline
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lol...unfortunately the retired guy gave me a negative number...which looking at the graph of the function proves that to be wrong...

whereas the guy who talked to the tutor had a reasonable answer of 2.25...
 
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Reply #14 - Dec 7th, 2003 at 8:51pm

Lethal.Ambition   Offline
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why look at the negative side of things?

All it takes is to remove the -

its not the SAT folks! Grin
 

Oderint Dum Metuant - Let them hate as long as they fear.&&Proud member of the =XE= Xtreme Eagles&&Oderint Dum Metuant&&
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