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Gliding Distance (Read 1486 times)
Reply #15 -
Jan 15
th
, 2010 at 4:33pm
chornedsnorkack
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Posts: 363
Suppose that you, say, have both engines wrecked at the top of the climb by features like ash, vultures or overheating the engines... and find yourself at 40 000 feet with no prospect of relighting and 170 tons of fuel with absolutely no use except to power the postcrash fire.
When and where would you rather dump it?
L/D depends only slightly on weight.
If it did not depend on weight at all then the distance you could glide would be independent on the weight. Jets at cruise altitude are decent gliders... Azores Glider covered 140 km, so if the engines had failed for other reasons, and the tanks had been full, the same distance would have been covered, only faster.
But it does depend on weight.
For one, Mach number depends on true air speed. If the best glide speed for a fully loaded, 340 t airplane at altitude were, say, 0,84 M then after dumping the fuel, at 170 t empty weight, the best glide would turn out to be just 0,6 M.
Actually, lowering M improves L/D, at least in subsonic range (Not sure how to pick best glide speed and weight at the range 1...1,5 M. If you have 90 tons of fuel you do not want powering post-crash fire, would you start dumping right away at FL600 and M2,0, or after you have successfully gone to FL300 and M0,9, or at the end of the trip below FL100?).
Now, how about Reynolds number? At small Mach numbers, how does decreasing the weight and thus TAS affect L/D?
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Reply #16 -
Jan 15
th
, 2010 at 7:31pm
beaky
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SaultFresh wrote
on Jan 15
th
, 2010 at 3:23pm:
Here's another question that I asked the same professor today, and he didn't exactly give me a straight answer. The thing with him is that he's quite a bit older of a fellow and he's got tonnes of experience, he's got every sort of license under the sun including an aerobatic's instructor rating so I asked him how to recover from a tail stall, the only thing he really told me was to pull back on the stick instead of forward, which didn't make a whole lot of sense, I then asked him about power settings for such a recovery and he wasn't too sure as the last time he had looked at such a procedure was at least three years ago... and the likelihood of this scenario ever happening at my school is slim to none as we are not allowed to fly in known icing conditions, both single engines and multi-engines owned by the school simply aren't rated for such conditions. Being a curious person who wants to know everything about everything, what is the procedure for such a scenario?
I dunno... tail stalls are more of a jet thing; I'm not sure. But it sort of makes sense (pitching up)- most horizontal stabs are angled relative to the fuselage so that they provide a downward force ("negative lift"). If that surface has stalled, that probably means its leading edge is
too
low (or ice accumulation is having the equivalent effect). So pitching up should reduce that "negative angle of attack" so that the stab starts doing its thing again.
Another indication that this is why is the fact that if that stab is providing down force, if it stalls, it stops producing down force... so the nose of the plane will try to pitch down, requiring you to pull back anyway.
Ask him if that's why... I'm curious myself, and probably wrong, because it seems so simple...
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Reply #17 -
Jan 15
th
, 2010 at 10:03pm
SaultFresh
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I'll have to ask him next week when I have his Human Factors class again... I'm sure he knows a bit more than he leads on to. The whole reason why it came up though was because he said he suspects that's what happened to that plane that went down last year in Buffalo, where they couldn't recover. He did however say that it's rare, the conditions have to be right, and it's hard to tell, because he did say the nose dips, so it could look like just a normal stall, in either case, it's kind of a scary thing, and I really have no idea what else could be done to recover other than that pulling back on the stick, which does make sense somewhat now. I have a feeling though he's not going to say much else about it, there might be a few others that I could ask about it though.
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Reply #18 -
Jan 15
th
, 2010 at 10:38pm
beaky
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Getting back to the heavier plane
climbing
scenario:
Let's forget the obvious problems associated with weight and its effect on takeoff roll and breaking out of ground effect... let's assume each pilot is already established at the desired climb rate to go from Point A to Point B, with Point B is at higher altitude, over a specific distance. Like, for instance, each plane is cruising at 1500 MSL, and starting at a highway intersection, they must begin climbing so that they cut a ribbon on poles atop a ridge at 5000 MSL, exactly 5 miles from the highway intersection. They must each climb exactly 3500 feet over 5 miles. We know they can both do it (we're assuming the heavy airplane is within limits, not over gross). But something will have to be different, for sure. Each plane will have to blend airspeed and vertical speed in different ways to achieve the same goal of alt/distance.
We know damn well that if the aim is to get to 5,000 MSL sooner, the lighter plane will win, because the thrust and A of A is less hampered by weight. But the goal is two-pronged: a specific altitude and a specific distance, at a specific angle, just like the gliding-to-land scenario. There is no time requirement.
I am certain that the heavier plane will have to climb at a higher airspeed to reach a given altitude over a given horizontal distance (all V-speeds go up with weight, even Vx and Vy, so whatever the desired rate of climb is, the heavier plane will need more airspeed to do it, assuming the same available thrust as the lighter plane).
But will it take less
time
? I don't know. I think it will, but I'm not sure. Can the heavy plane match the lighter plane's rate of climb, and still move forward faster? Or will it have to compromise, logging the same amount of time as the lighter plane... or more?
We know that the indicated airspeed shows the velocity of the
relative wind
, so airspeed in a climb is not the same as groundspeed with no wind, as it would be if you were flying level between two points at the same altitude. Most of us figure our time-to-climb based on horizontal distance... works well enough with a light single most of the time, but this is not entirely accurate, unless our climb angle is such that the hypotenuse of the triangle (the actual path through the air) equals the base (the distance over the surface). And it rarely does.
So... maybe that is where the tale is told... but wait, no; each plane is flying a path fixed by the dimensions of the same right triangle... the actual path traveled in this steady climb represents the same distance. A higher airspeed, it would seem,
should
yield a shorter time along that path. But can a heavier airplane really do this trick faster? Doesn't seem right. I am an empiricist by nature... I'd have to fly the two planes myself before I can answer that.
Whatever the difference, I think in most cases it would be negligible. The lighter plane will have an advantage initially, during the time it is accelerating, on the ground and in ground effect, as it approaches the speed required to yield the desired climb rate. The difference could be very pronounced, so I think
from a dead stop on the ground
to the altitude/distance waypoint (Point B), the lighter plane would complete the task in less time, even if the heavier plane can climb at a higher airspeed at the same vertical speed once the climb is established.
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Reply #19 -
Jan 15
th
, 2010 at 10:59pm
beaky
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chornedsnorkack wrote
on Jan 15
th
, 2010 at 4:33pm:
Now, how about Reynolds number? At small Mach numbers, how does decreasing the weight and thus TAS affect L/D?
I need to look up "Reynolds number", LOL, but my "horseback guesstimate" is that TAS, like any airspeed, will have to
increase with weight
to yield the desired L/D (not the L/D
speed
, but the actual lift-to-drag ratio). Look at it this way: weight, like load factor, has to be considered, even though they don't call it "L/D/W". I know odd things happen in the transsonic zone, but I'll wager my two cents that the same rule about weight applies in that case.
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Reply #20 -
Jan 15
th
, 2010 at 11:02pm
Brett_Henderson
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We're gonna have to discuss this stuff over a beer sometime.
You attack this stuff a lot like I do.. your attempt to understand it yourself, is driven from the perspective of explaining it to others. 'cept I'm more likely to accept the mysterious, aeordynamic stuff, and put hard math aside (ala that debate over what causes an airplane to fly..
)
There's a "Devil's Advocate" glitch in my attempt to fog the gliding scenario.. because I DO accept that the gliding distances are effectively equal on paper. My statement that our stored energy is a constant is flawed. Your explanation on climbs kinda points it out. Gravity itself is a constant, but the climb to get the heavier airplane up there, has stored more energy. It took a longer application of engine thrust. So the heavier airplane has more energy at it's disposal (eaten up by the higher airspeed during the glide). When the dust settles.. the conservation of energy dictates that both airplanes can glide equal distances.
HOWEVER.. my countless times going from TPA to a runway, in every load-range imaginable, STILL has me believing that the 172 with just me in it, will make the runway after engine failure on base, when the 172 with two freinds and a bunch of fuel will not.
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Reply #21 -
Jan 16
th
, 2010 at 2:07am
SaultFresh
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Flight Instructor, CYKZ
Woodbridge, Ontario
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I kind of have a sneaking suspicion that those two climbing planes would make it relatively closer to the same time. My reasoning is that, while both airplanes will have to increase their airspeed as height increases to maintain the rate of climb they want (assuming they're both climbing at the same rate), then the heavier airplane will have to be traveling at a faster velocity than the lighter one, simply because of drag I think. I think it's very possible to get the two planes at point B at the same time.
Reynolds number on the other hand has more to do with airflow, and can be used to find where the transition point between laminar and turbulent airflow over a wing. I can't really make some of these symbols... so bare with me... Reynolds number can be expressed as Re= (VL)/v, where V is the velocity in ft/s, L is the exposed m.a.c., and v is the kinematic viscosity, which I had to pull that one off of wikipedia
http://en.wikipedia.org/wiki/Reynolds_number#Transition_Reynolds_number
... it's not even listed in my own notes. The higher V is, the higher the Reynold's number. V is comprised of two variables, Mach number, and the speed of sound "a". Both variables can change, so if you're mach number is higher, and "a" has remained constant, than you're Reynolds number will be higher, meaning you will have more turbulent flow over the wings than laminar flow, which means more drag. How's that for a whole lot of late night information just being thrown into the wing... haha, anyhow, for the dumping of the fuel, there's probably a checklist to follow that would include when an appropriate time for that would be. If it were me, McGyvering my way through such a scenario, I would probably dump it sooner than later, just to give me more time to set up, and less stuff to worry about later. I mean, if you dump it after giving up hope on the engines, than you'll have time to set up the attitude you want (because it will change), and it's one less thing to worry about later on. Now that could be the wrong thing to do, I certainly don't know, I mean, traveling at such a quick speed brings so many different variables like possibly compressible flow which depends how fast you really are traveling and all sorts of drag. Kind of makes sense to me to get light as quick as possible to shed the drag, but again, I don't know, I've never traveled anywhere near as fast, or as high, as the speeds and altitudes. Also, please correct me if I made any mistakes in attempting to explain Reynolds number, not that I need this information for the slow flying in small planes that I do, but it never hurts to store some of this stuff away in the back of the brain.
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Reply #22 -
Jan 16
th
, 2010 at 6:16am
Brett_Henderson
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EVERY OUTER MARKER SHOULD
BE AN NDB
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Quote:
I kind of have a sneaking suspicion that those two climbing planes would make it relatively closer to the same time. My reasoning is that, while both airplanes will have to increase their airspeed as height increases to maintain the rate of climb they want (assuming they're both climbing at the same rate), then the heavier airplane will have to be traveling at a faster velocity than the lighter one, simply because of drag I think. I think it's very possible to get the two planes at point B at the same time.
If point B is distance from takeoff, AND an altitude.. the heavier airplane would need more thrust than the lighter.. AND bigger wings to get to the same point, at the same time.
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Reply #23 -
Jan 16
th
, 2010 at 7:46am
DaveSims
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beaky wrote
on Jan 15
th
, 2010 at 7:31pm:
SaultFresh wrote
on Jan 15
th
, 2010 at 3:23pm:
Here's another question that I asked the same professor today, and he didn't exactly give me a straight answer. The thing with him is that he's quite a bit older of a fellow and he's got tonnes of experience, he's got every sort of license under the sun including an aerobatic's instructor rating so I asked him how to recover from a tail stall, the only thing he really told me was to pull back on the stick instead of forward, which didn't make a whole lot of sense, I then asked him about power settings for such a recovery and he wasn't too sure as the last time he had looked at such a procedure was at least three years ago... and the likelihood of this scenario ever happening at my school is slim to none as we are not allowed to fly in known icing conditions, both single engines and multi-engines owned by the school simply aren't rated for such conditions. Being a curious person who wants to know everything about everything, what is the procedure for such a scenario?
I dunno... tail stalls are more of a jet thing; I'm not sure. But it sort of makes sense (pitching up)- most horizontal stabs are angled relative to the fuselage so that they provide a downward force ("negative lift"). If that surface has stalled, that probably means its leading edge is
too
low (or ice accumulation is having the equivalent effect). So pitching up should reduce that "negative angle of attack" so that the stab starts doing its thing again.
Another indication that this is why is the fact that if that stab is providing down force, if it stalls, it stops producing down force... so the nose of the plane will try to pitch down, requiring you to pull back anyway.
Ask him if that's why... I'm curious myself, and probably wrong, because it seems so simple...
You have it right rotty. The tailplane is essentially an upside down wing. Think about how you correct a stall for the wing, you pitch down to reduce AOA. On the tail, by pulling back you raise the elevators, which reduces the AOA, and hopefully gets the tail flying. This may have been one of the factors in the Buffalo crash last year. The crew failed to recognize a tail stall, and did not take the appropriate action. A tail stall and normal stall will seem similar, the aircraft seems to quit flying and pitches down. Unfortunately the correct action for each stall is reverse.
Dave
www.flymcw.com
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Reply #24 -
Jan 16
th
, 2010 at 1:34pm
beaky
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Brett_Henderson wrote
on Jan 16
th
, 2010 at 6:16am:
Quote:
I kind of have a sneaking suspicion that those two climbing planes would make it relatively closer to the same time. My reasoning is that, while both airplanes will have to increase their airspeed as height increases to maintain the rate of climb they want (assuming they're both climbing at the same rate), then the heavier airplane will have to be traveling at a faster velocity than the lighter one, simply because of drag I think. I think it's very possible to get the two planes at point B at the same time.
If point B is distance from takeoff, AND an altitude.. the heavier airplane would need more thrust than the lighter.. AND bigger wings to get to the same point, at the same time.
But what if Point A was not takeoff, but some random point when climb is firmly established?
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Reply #25 -
Jan 16
th
, 2010 at 3:15pm
Brett_Henderson
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EVERY OUTER MARKER SHOULD
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beaky wrote
on Jan 16
th
, 2010 at 1:34pm:
Brett_Henderson wrote
on Jan 16
th
, 2010 at 6:16am:
Quote:
I kind of have a sneaking suspicion that those two climbing planes would make it relatively closer to the same time. My reasoning is that, while both airplanes will have to increase their airspeed as height increases to maintain the rate of climb they want (assuming they're both climbing at the same rate), then the heavier airplane will have to be traveling at a faster velocity than the lighter one, simply because of drag I think. I think it's very possible to get the two planes at point B at the same time.
If point B is distance from takeoff, AND an altitude.. the heavier airplane would need more thrust than the lighter.. AND bigger wings to get to the same point, at the same time.
But what if Point A was not takeoff, but some random point when climb is firmly established?
I think the same would apply.
An "A-to-B" glide (
where the effective hypotenuse is the same
), is different than an "A-to-B" climb.
We all agree (grudgingly) that identical airplanes of different (reasonable) loads
can
execute the same glide hypotenuse... because a glide counts on the long-since stored energy of the weight already AT altitude. More weight.. more stored energy.
And of course there's no argument that a heavily loaded airplane cannot climb the same hypotenuse as an identical, lighter loaded airplane... because the heavier load does not bring its own, extra energy along for the climb.
A quick glance at a C172 takeoff chart shows a 35% higher FPM climb-rate at
Vy
for a 1700lb airplane, compared to a 2300lb airplane.
This applies to any altitude increase.. (doesn't it ?)
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Reply #26 -
Jan 16
th
, 2010 at 7:31pm
beaky
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Brett_Henderson wrote
on Jan 16
th
, 2010 at 3:15pm:
A quick glance at a C172 takeoff chart shows a 35% higher FPM climb-rate at
Vy
for a 1700lb airplane, compared to a 2300lb airplane.
Right...that shows that there is a rate of climb beyond the capability of the heavier aircraft (which actually jibes with common sense, whew!) .
But in our exercise, we're not merely trying to get the best rate of climb, or even the best distance to climb... we're trying to fly the same path at the same angle.
It's a vertical
and
horizontal distance problem.
The assumption is that the heavier airplane will need to fly at a higher IAS just to climb fast enough to manage it... but will it get there faster?
That's all I will say about this for now; it's making my head hurt.
this is what happens when you don't get to fly often enough...
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Reply #27 -
Jan 16
th
, 2010 at 8:27pm
Brett_Henderson
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EVERY OUTER MARKER SHOULD
BE AN NDB
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Posts: 3593
Quote:
The assumption is that the heavier airplane will need to fly at a higher IAS just to climb fast enough to manage it... but will it get there faster?
That's moot, in our discussion.. we're assuming a full power-climb, so the heavier airplane doesn't have the luxury that the heavier "glider" has (available energy that varies by load).
You might be able to get to point
B
at Vx, but that throws another variable in there. At Vy, the heavier airplane will have to fly a big "
S
" (lengthening the hypotenuse) to reach B without having to bouble back (an that introduces the lost lift during the turns..
)
Yeah.. my head hurts too..
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Reply #28 -
Jan 16
th
, 2010 at 8:55pm
SaultFresh
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Flight Instructor, CYKZ
Woodbridge, Ontario
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beaky wrote
on Jan 16
th
, 2010 at 7:31pm:
[quote author=Brett_Henderson link=1263508816/25#25 date=1263672951]
this is what happens when you don't get to fly often enough...
Definitely agree with this... haha... all this bad weather is ironically keeping me from an instrument rating... haha...
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Reply #29 -
Jan 17
th
, 2010 at 8:57pm
olderndirt
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Flying is PFM
Rochester, WA
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beaky wrote
on Jan 16
th
, 2010 at 7:31pm:
making my head hurt.
Been reading along - nodded off a couple of times and my head, teeth and butt hurt. Still think my avatar says it all about flying
.
THIS IS NOT A PANAM CLIPPER
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